TSTP Solution File: SEV043^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SEV043^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 19:24:07 EDT 2023

% Result   : Theorem 3.41s 3.66s
% Output   : Proof 3.41s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SEV043^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13  % Command    : duper %s
% 0.12/0.34  % Computer : n017.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit   : 300
% 0.12/0.34  % WCLimit    : 300
% 0.12/0.34  % DateTime   : Thu Aug 24 03:28:09 EDT 2023
% 0.12/0.34  % CPUTime    : 
% 3.41/3.66  SZS status Theorem for theBenchmark.p
% 3.41/3.66  SZS output start Proof for theBenchmark.p
% 3.41/3.66  Clause #0 (by assumption #[]): Eq
% 3.41/3.66    (Not
% 3.41/3.66      (∀ (Xp : a → a → Prop),
% 3.41/3.66        And (∀ (Xx Xy : a), Xp Xx Xy → Xp Xy Xx) (∀ (Xx Xy Xz : a), And (Xp Xx Xy) (Xp Xy Xz) → Xp Xx Xz) →
% 3.41/3.66          ∀ (Xx Xy : a), Xp Xx Xy → Xp Xx Xx))
% 3.41/3.66    True
% 3.41/3.66  Clause #1 (by clausification #[0]): Eq
% 3.41/3.66    (∀ (Xp : a → a → Prop),
% 3.41/3.66      And (∀ (Xx Xy : a), Xp Xx Xy → Xp Xy Xx) (∀ (Xx Xy Xz : a), And (Xp Xx Xy) (Xp Xy Xz) → Xp Xx Xz) →
% 3.41/3.66        ∀ (Xx Xy : a), Xp Xx Xy → Xp Xx Xx)
% 3.41/3.66    False
% 3.41/3.66  Clause #2 (by clausification #[1]): ∀ (a_1 : a → a → Prop),
% 3.41/3.66    Eq
% 3.41/3.66      (Not
% 3.41/3.66        (And (∀ (Xx Xy : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xy Xx)
% 3.41/3.66            (∀ (Xx Xy Xz : a), And (skS.0 0 a_1 Xx Xy) (skS.0 0 a_1 Xy Xz) → skS.0 0 a_1 Xx Xz) →
% 3.41/3.66          ∀ (Xx Xy : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xx Xx))
% 3.41/3.66      True
% 3.41/3.66  Clause #3 (by clausification #[2]): ∀ (a_1 : a → a → Prop),
% 3.41/3.66    Eq
% 3.41/3.66      (And (∀ (Xx Xy : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xy Xx)
% 3.41/3.66          (∀ (Xx Xy Xz : a), And (skS.0 0 a_1 Xx Xy) (skS.0 0 a_1 Xy Xz) → skS.0 0 a_1 Xx Xz) →
% 3.41/3.66        ∀ (Xx Xy : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xx Xx)
% 3.41/3.66      False
% 3.41/3.66  Clause #4 (by clausification #[3]): ∀ (a_1 : a → a → Prop),
% 3.41/3.66    Eq
% 3.41/3.66      (And (∀ (Xx Xy : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xy Xx)
% 3.41/3.66        (∀ (Xx Xy Xz : a), And (skS.0 0 a_1 Xx Xy) (skS.0 0 a_1 Xy Xz) → skS.0 0 a_1 Xx Xz))
% 3.41/3.66      True
% 3.41/3.66  Clause #5 (by clausification #[3]): ∀ (a_1 : a → a → Prop), Eq (∀ (Xx Xy : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xx Xx) False
% 3.41/3.66  Clause #6 (by clausification #[4]): ∀ (a_1 : a → a → Prop), Eq (∀ (Xx Xy Xz : a), And (skS.0 0 a_1 Xx Xy) (skS.0 0 a_1 Xy Xz) → skS.0 0 a_1 Xx Xz) True
% 3.41/3.66  Clause #7 (by clausification #[4]): ∀ (a_1 : a → a → Prop), Eq (∀ (Xx Xy : a), skS.0 0 a_1 Xx Xy → skS.0 0 a_1 Xy Xx) True
% 3.41/3.66  Clause #8 (by clausification #[6]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.41/3.66    Eq (∀ (Xy Xz : a), And (skS.0 0 a_1 a_2 Xy) (skS.0 0 a_1 Xy Xz) → skS.0 0 a_1 a_2 Xz) True
% 3.41/3.66  Clause #9 (by clausification #[8]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.41/3.66    Eq (∀ (Xz : a), And (skS.0 0 a_1 a_2 a_3) (skS.0 0 a_1 a_3 Xz) → skS.0 0 a_1 a_2 Xz) True
% 3.41/3.66  Clause #10 (by clausification #[9]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.41/3.66    Eq (And (skS.0 0 a_1 a_2 a_3) (skS.0 0 a_1 a_3 a_4) → skS.0 0 a_1 a_2 a_4) True
% 3.41/3.66  Clause #11 (by clausification #[10]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.41/3.66    Or (Eq (And (skS.0 0 a_1 a_2 a_3) (skS.0 0 a_1 a_3 a_4)) False) (Eq (skS.0 0 a_1 a_2 a_4) True)
% 3.41/3.66  Clause #12 (by clausification #[11]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.41/3.66    Or (Eq (skS.0 0 a_1 a_2 a_3) True) (Or (Eq (skS.0 0 a_1 a_2 a_4) False) (Eq (skS.0 0 a_1 a_4 a_3) False))
% 3.41/3.66  Clause #13 (by clausification #[5]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.41/3.66    Eq (Not (∀ (Xy : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xy → skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 1 a_1 a_2))) True
% 3.41/3.66  Clause #14 (by clausification #[13]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.41/3.66    Eq (∀ (Xy : a), skS.0 0 a_1 (skS.0 1 a_1 a_2) Xy → skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 1 a_1 a_2)) False
% 3.41/3.66  Clause #15 (by clausification #[14]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.41/3.66    Eq (Not (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3) → skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 1 a_1 a_2))) True
% 3.41/3.66  Clause #16 (by clausification #[15]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.41/3.66    Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3) → skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 1 a_1 a_2)) False
% 3.41/3.66  Clause #17 (by clausification #[16]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 2 a_1 a_2 a_3)) True
% 3.41/3.66  Clause #18 (by clausification #[16]): ∀ (a_1 : a → a → Prop) (a_2 : a), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 1 a_1 a_2)) False
% 3.41/3.66  Clause #19 (by superposition #[17, 12]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.41/3.66    Or (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) a_3) True)
% 3.41/3.66      (Or (Eq True False) (Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_4) a_3) False))
% 3.41/3.66  Clause #20 (by clausification #[7]): ∀ (a_1 : a → a → Prop) (a_2 : a), Eq (∀ (Xy : a), skS.0 0 a_1 a_2 Xy → skS.0 0 a_1 Xy a_2) True
% 3.41/3.67  Clause #21 (by clausification #[20]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a), Eq (skS.0 0 a_1 a_2 a_3 → skS.0 0 a_1 a_3 a_2) True
% 3.41/3.67  Clause #22 (by clausification #[21]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a), Or (Eq (skS.0 0 a_1 a_2 a_3) False) (Eq (skS.0 0 a_1 a_3 a_2) True)
% 3.41/3.67  Clause #23 (by superposition #[22, 17]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a),
% 3.41/3.67    Or (Eq (skS.0 0 (fun x x_1 => a_1 x x_1) (skS.0 2 a_1 a_2 a_3) (skS.0 1 a_1 a_2)) True) (Eq False True)
% 3.41/3.67  Clause #24 (by betaEtaReduce #[23]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a), Or (Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3) (skS.0 1 a_1 a_2)) True) (Eq False True)
% 3.41/3.67  Clause #25 (by clausification #[24]): ∀ (a_1 : a → a → Prop) (a_2 a_3 : a), Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_3) (skS.0 1 a_1 a_2)) True
% 3.41/3.67  Clause #28 (by clausification #[19]): ∀ (a_1 : a → a → Prop) (a_2 a_3 a_4 : a),
% 3.41/3.67    Or (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) a_3) True) (Eq (skS.0 0 a_1 (skS.0 2 a_1 a_2 a_4) a_3) False)
% 3.41/3.67  Clause #29 (by superposition #[28, 25]): ∀ (a_1 : a → a → Prop) (a_2 : a),
% 3.41/3.67    Or (Eq (skS.0 0 (fun x x_1 => a_1 x x_1) (skS.0 1 (fun x x_1 => a_1 x x_1) a_2) (skS.0 1 a_1 a_2)) True)
% 3.41/3.67      (Eq False True)
% 3.41/3.67  Clause #30 (by betaEtaReduce #[29]): ∀ (a_1 : a → a → Prop) (a_2 : a), Or (Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 1 a_1 a_2)) True) (Eq False True)
% 3.41/3.67  Clause #31 (by clausification #[30]): ∀ (a_1 : a → a → Prop) (a_2 : a), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) (skS.0 1 a_1 a_2)) True
% 3.41/3.67  Clause #32 (by superposition #[31, 18]): Eq True False
% 3.41/3.67  Clause #34 (by clausification #[32]): False
% 3.41/3.67  SZS output end Proof for theBenchmark.p
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